Lets Play:
The father’s age is six times his son’s age. Six years hence the age of the father will be
four times that of his son’s age. Find the present ages (in years) of the son and father.
In this we can take two variables father’s age and the son’s age
STEP 1:
● Let’s take the present age of both the father’s age as x and the son’s age as y :
x = 6y ——– (1) (father’s age is six times his son’s age)
After six years,
x = 4y ———– (2) (the age of the father will be four times that of his son age)
STEP 2
● lets combine both the equations top form a resulting equation.
x + 6 = 4(y + 6)
x – 4y = 18 ———— (3)
STEP 3:
● Substitute equation 1 in 3
6y – 4y = 18
2y = 18
y = 9
● Sub y = 9 in eqn 1
So x = 6(9)
X = 54
Hence, The present age of the father is 54 and the present age of the son is 9.

TIPS FOR TRICKS: If you doubt whether it is an answer or not put the value of x and y in equations 1
and 2 it will perfectly equate otherwise it won’t be an answer